3[x+1]+4=2[x+1]+x

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Solution for 3[x+1]+4=2[x+1]+x equation:


Simplifying
3[x + 1] + 4 = 2[x + 1] + x

Reorder the terms:
3[1 + x] + 4 = 2[x + 1] + x
[1 * 3 + x * 3] + 4 = 2[x + 1] + x
[3 + 3x] + 4 = 2[x + 1] + x

Reorder the terms:
3 + 4 + 3x = 2[x + 1] + x

Combine like terms: 3 + 4 = 7
7 + 3x = 2[x + 1] + x

Reorder the terms:
7 + 3x = 2[1 + x] + x
7 + 3x = [1 * 2 + x * 2] + x
7 + 3x = [2 + 2x] + x

Combine like terms: 2x + x = 3x
7 + 3x = 2 + 3x

Add '-3x' to each side of the equation.
7 + 3x + -3x = 2 + 3x + -3x

Combine like terms: 3x + -3x = 0
7 + 0 = 2 + 3x + -3x
7 = 2 + 3x + -3x

Combine like terms: 3x + -3x = 0
7 = 2 + 0
7 = 2

Solving
7 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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